IT/Programming / / 2023. 4. 20. 13:02

[JAVA, HTML] Servlet(web.xml수정)

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web.xml을 수정해야 HTML과 Servlet파일을 이어줄 수 있다.

web.xml 위치 :WebContent/Web-INF/web.xml

-> 이클립스 기준 , 하단에 Design과 Source탭 존재

-> Source탭에서 코드 수정

 

 

예제 1:

parameter.html에서 이름과 나이를 받아 성인인지 청소년인지 구분하여 출력

parapeter.html : 이름과 나이를 받아 submit

ParamServlet.java : 정보를 받아 계산 후 출력

 

Web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
  <display-name>7-Servlet</display-name>

//수정하는 곳
  <servlet
    <servlet-name>param</servlet-name>
    <servlet-class>com.param.ParamServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>param</servlet-name>
    <url-pattern>/ParamServlet</url-pattern>
  </servlet-mapping>
  <servlet>
    <servlet-name>hello</servlet-name>
    <servlet-class>com.hello.HelloServlet</servlet-class>
  </servlet>


  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
</web-app
 

ParamServlet.java

package com.param;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class ParamServlet extends HttpServlet {
	private static final long serialVersionUID = 1L;
    public ParamServlet() {
        super();
    }
	protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		//1. 데이터
		request.setCharacterEncoding("UTF-8");//POST방식(2바이트로 넘어감) 한글깨짐방식
		String name = request.getParameter("name");
		int age = Integer.parseInt(request.getParameter("age"));
		
		//2. 응답
		response.setContentType("text/html;charset=UTF-8");
		//이후의 문자열을 html로 인식해라
		
		PrintWriter out = response.getWriter();//생성
		out.println("<html>");
		out.println("<head>");
		out.println("<title>Servlet</title>");
		out.println("</head>");
		out.println("<body>");
		out.println(name + "님의 나이는 "+age+"살 이므로, ");
		if(age >= 20 ) out.println("성인입니다.");
		else out.println("청소년입니다.");
		out.println("</body");
		out.println("</html");
	}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		doGet(request, response);
	}
}
 

parameter.html

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
<form name ="" method = "POST" action ="http://localhost:8080/7-Servlet/ParamServlet">
	<table border ="1">
		<tr>
			<td width ="70" align ="center">이름</td>
			<td><input type ="text" name ="name"></td>
		</tr>
		
		<tr>
			<td width ="70" align ="center">나이</td>
			<td><input type ="text" name ="age"></td>
		</tr>
		
		<tr>
			<td colspan="2" align="center">
				<input type ="submit" value="보내기">
				<input type ="reset" value="취소">
			</td>
		</tr>
		
	</table>
</form>
</body>
</html>
 

 

예제 결과창

 

 

 

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